1/6x^2+1/3x=5/2

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Solution for 1/6x^2+1/3x=5/2 equation: 


x in (-oo:+oo)

(1/6)*x^2+(1/3)*x = 5/2 // - 5/2

(1/6)*x^2+(1/3)*x-(5/2) = 0

(1/6)*x^2+(1/3)*x-5/2 = 0

1/6*x^2+1/3*x-5/2 = 0

DELTA = (1/3)^2-(-5/2*1/6*4)

DELTA = 16/9

DELTA > 0

x = ((16/9)^(1/2)-1/3)/(1/6*2) or x = (-(16/9)^(1/2)-1/3)/(1/6*2)

x = 3 or x = -5

x in { -5, 3 }

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